3[2+q]+15=21+3q

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Solution for 3[2+q]+15=21+3q equation:


Simplifying
3[2 + q] + 15 = 21 + 3q
[2 * 3 + q * 3] + 15 = 21 + 3q
[6 + 3q] + 15 = 21 + 3q

Reorder the terms:
6 + 15 + 3q = 21 + 3q

Combine like terms: 6 + 15 = 21
21 + 3q = 21 + 3q

Add '-21' to each side of the equation.
21 + -21 + 3q = 21 + -21 + 3q

Combine like terms: 21 + -21 = 0
0 + 3q = 21 + -21 + 3q
3q = 21 + -21 + 3q

Combine like terms: 21 + -21 = 0
3q = 0 + 3q
3q = 3q

Add '-3q' to each side of the equation.
3q + -3q = 3q + -3q

Combine like terms: 3q + -3q = 0
0 = 3q + -3q

Combine like terms: 3q + -3q = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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